5y^2-28y-96=0

Solution for 5y^2-28y-96=0 equation:

5y^2-28y-96=0

a = 5; b = -28; c = -96;
Δ = b2-4ac
Δ = -282-4·5·(-96)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-52}{2*5}=\frac{-24}{10}
=-2+2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+52}{2*5}=\frac{80}{10}
=8
$